Question

There are only blue sweets, green sweets and red sweets in a box. The ratio of the number of blue sweets to the number of green sweetsis 2:7 The ratio of the number of green sweets to the number of red sweets is 3:1 there are less than 140 sweets in the box . What is the greatest possible numberof red sweets in the box? Your final answer must include, 'red sweets'.

Answer 1

Answer:

According to question if we observe, number of red sweets are the least

It 's only 1%

PLZ, PLZ MARK AS BRAINLIAST..

Answer 2

The greatest possible number of red sweets is 28

Step-by-step explanation:

Let the common ratio between blue and red sweets be x

Then,

Number of blue sweets = 2x

Number of green sweets = 7x

If the common ratio between the green and red sweets be y

Then,

Number of green sweets = 3y

Number of red sweets = y

Here the number of green sweets must be equal

Therefore,

$7x=3y$

Also the sum of all of them is 140

Thus,

$2x+3y+y<140$

$\implies 2x+4y<140$

$\implies x+2y<70$

$\implies x+2\times\frac{7x}{3}<70$

$\implies 3x+14x<210$

$\implies 17x<210$

$\implies x<\frac{210}{17}$

$\implies x<12.36$

x should be a whole number

Therefore, $x=12$

And the sum of all the sweets will be 136

Therefore,

$y=\frac{7\times 12}{3}$

$\implies y=28$

Thus the greatest possible number of red sweets is 28

Hope this helps.