Question

There are seven children standing in a lije not all fo whom havce the same number of cakes with them if the first child distributes his cake amoung the remaining six children such that he doubles

Answer 1

Answer:

Step-by-step explanation:

Let the 7 children have a,b,c,d,e,f,g cakes respectively.

First statement: The first child distributes his cake such that he is left with 4 cakes and rest have double their initial number of cakes:

hence:

a-(b+c+d+e+f+g) = 4 --- (i)

Second statement: the 2nd boy takes 2 cakes each from every one and is still 3 short of initial value of 1st.

Hence:

b+2 cakes(6 children) = a-3

or a-b = 15 --- (ii)

substituting this value in eq - 1.

a-b -(c+d+e+f+g) = 4

We get (c+d+e+f+g) = 11.

Hope it helps you...