There are seven pairs of black shoes and five pairs of white shoes. They are all put into a box and shoes are drawn one at a time. To ensure that at least one pair of black shoes are taken out, what is the number of shoes required to be drawn out?
Answers
The number of shoes required to drawn out, to ensure that at least one pair of black shoes are taken out is 4*2+2=10
Given:
7 pairs of black shoes
5 pairs of white shoes
To Find:
Number of draws needed to draw one pair of black shoes
Explanation:
A pair of shoes has a left side and a right side. So drawing 2 left sides of the shoes does not constitute to a pair fo shoes. A left side and a right side is needed.
Solution:
Find the number of white shoes:
Number of pairs = 5
Number of shoes = 5 x 2
Number of shoes = 10
Find the number of black shoes:
Number of pairs = 7
Number of shoes = 7 x 2
Number of shoes = 14
Consider the worst case scenarios:
All the white shoes were drawn before any of the black shoes were drawn.
Number of draws = 10
Now we are left with all the black shoes. All the left sides were drawn.
Number of draws = 7
Now whatever remains are all the right side of the black shoes. So any one draw from this stack will give us a pair.
Number of draws = 1
Find the total number of draws needed:
Total number of draws needed = 10 + 7 + 1
Total number of draws needed = 18
Answer: 18 draws are needed to ensure that there are at least one pair of black shoes.