There are several tea cups in the kitchen,some with handles and the others without handles. The number of ways of selecting two cups without a handle and three with a handle is exactly 1200. what is the maximum possible number of cups in the kitchen?
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Let the no of cups without handle be X
N
with handle be y
now solve the eqn
2x + 3y = 1200
N
with handle be y
now solve the eqn
2x + 3y = 1200
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