THERE ARE SIX ANGLES AT A POINT . ONE OF THEM IS 50 AND ALL THE OTHER FIVE ANGLES ARE EQUAL. WHAT IS THE MEASURE OF EACH OF THOSE EQUAL ANGLES
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Answered by
30
so all angle are be a,b,c,d and e
let angle a is x
a=b=c=d=e=x
then a+b+c+d+e+50°=360
x+x+x+x+x+50=360. ( a = x )
5x=360-50
5x=310
x=310/5
x=62°
then all angles are 62°
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let angle a is x
a=b=c=d=e=x
then a+b+c+d+e+50°=360
x+x+x+x+x+50=360. ( a = x )
5x=360-50
5x=310
x=310/5
x=62°
then all angles are 62°
MARK ME BRAINLIEST
lakshay118:
thankyou so much
Answered by
13
Answer:
Step-by-step explanation:
so all angle are be a,b,c,d and e
let angle a is x
a=b=c=d=e=x
then a+b+c+d+e+50°=360
x+x+x+x+x+50=360. ( a = x )
5x=360-50
5x=310
x=310/5
x=62°
then all angles are 62°
MARK ME BRAINLIEST
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