Math, asked by lakshay118, 1 year ago

THERE ARE SIX ANGLES AT A POINT . ONE OF THEM IS 50 AND ALL THE OTHER FIVE ANGLES ARE EQUAL. WHAT IS THE MEASURE OF EACH OF THOSE EQUAL ANGLES

Answers

Answered by sagarkes
30
so all angle are be a,b,c,d and e
let angle a is x
a=b=c=d=e=x
then a+b+c+d+e+50°=360
x+x+x+x+x+50=360. ( a = x )
5x=360-50
5x=310
x=310/5
x=62°
then all angles are 62°


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Answered by ravindrabansod26
13

Answer:

Step-by-step explanation:

so all angle are be a,b,c,d and e

let angle a is x

a=b=c=d=e=x

then a+b+c+d+e+50°=360

x+x+x+x+x+50=360. ( a = x )

5x=360-50

5x=310

x=310/5

x=62°

then all angles are 62°

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