Question

There are six bells which rings at the interval of 2,4,6,8,10 and 12 minutes all the six bells rungs together at 8:00 a.m find out the time when they will ring again together

Answer 1

10:00 a.m.
LCM of 2,4,6,8,10,12 is 120. Therefore that is the minimum time all the bells will ring at.
8:00 am + 120 mins (2 hours) will be 10:00 am.

Hope this helps!

Answer 2

Answer: They will ring again together at 8:24 a.m.

Step-by-step explanation:

Since we have given that

Number of bells = 6

Ring at the interval of 2,4,6,8,10 and 12 minutes.

So, when the six bells rungs together at 8:00 a.m.

We need to find the time when they will ring again together.

First we take the L.C.M. of 2,4,6,8,10,12,=24 minutes

So, they will ring again together at 8:24 a.m.