Math, asked by skpillai636, 2 months ago

There are six cards in a box, each bearing a number from 0 to 5. Find the probability of each of the following events, that a card drawn shows, (i) a natural number. (ii) a number less than 1. (iii) a whole number.

Answers

Answered by ajsheetal
5

Answer:

total no. of cards = 6

i) no. of natural numbers in 6 cards = 5

probability = 5/6

ii) a no. less than 1 = 1

probability = 1/6

iii) whole number = 6

probability = 6/6 = 1

I hope it helps you.

Answered by PriyankaPriyanka
11

Answer:

Number from 0 to 5 = 0, 1, 2, 3, 4,5

Total number = 6

1) A Natural number

=> Natural numbers = 1, 2, 3, 4, 5

Total number from 0 to 5 = 5

Therefore, Probability coming natural numbers = 5/6.

2) A number less than 1.

=> A number less than 1 = 0

Total number less than 1 = 1

Therefore, Probability coming a number less than 1 = 1/6

3) a whole number

=> Whole number = 0, 1, 2, 3, 4, 5

Total whole number = 6

Therefore, Probability coming a whole number is greater than 5 = 0/6 = 0

Step-by-step explanation:

Sorry, for late answer.

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