There are six cards in a box, each bearing a number from 0 to 5. Find the probability of each of the following events, that a card drawn shows, (i) a natural number. (ii) a number less than 1. (iii) a whole number.
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Answered by
5
Answer:
total no. of cards = 6
i) no. of natural numbers in 6 cards = 5
probability = 5/6
ii) a no. less than 1 = 1
probability = 1/6
iii) whole number = 6
probability = 6/6 = 1
I hope it helps you.
Answered by
11
Answer:
Number from 0 to 5 = 0, 1, 2, 3, 4,5
Total number = 6
1) A Natural number
=> Natural numbers = 1, 2, 3, 4, 5
Total number from 0 to 5 = 5
Therefore, Probability coming natural numbers = 5/6.
2) A number less than 1.
=> A number less than 1 = 0
Total number less than 1 = 1
Therefore, Probability coming a number less than 1 = 1/6
3) a whole number
=> Whole number = 0, 1, 2, 3, 4, 5
Total whole number = 6
Therefore, Probability coming a whole number is greater than 5 = 0/6 = 0
Step-by-step explanation:
Sorry, for late answer.
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