Question

there are six marbles in a box with numbers 1 to 6 marked on each of them. what is the probability of drawing a marble with even number marked on it ?

Answer 1

Answer:

Total number of marbles = 6

So n(s) = 6

Number of marbles marked with 2 = 1

n(e) = 1

Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\

Total number of outcomes

Number of favourable outcomes

=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}=

n(s)

n(e)

=

6

1

ii) Total number of marbles = 6

n(s) = 6

Number of marbles marked 5 = 1

Answer 2

Answer:

Question:-

There are six marbles in a box with numbers 1 to 6 marked on each of them. what is the probability of drawing a marble with even number marked on it ?

$\purple{\rule{45pt}{7pt}}\red{\rule{45pt}{7pt}}\pink{\rule{45pt}{7pt}}\blue{\rule{45pt}{7pt}}$

$\large \bf \red{Answer}$

$\huge{\boxed{\boxed{\tt \purple{\frac{1}{6}}}}}$

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(i) Number of marble with number 2 on it = 1

therefore Probability of getting a marble with number 2

=number of favourable outcomes

number of possible outcomes

$\implies{\boxed{\tt \red{\frac{1}{6}}}}$

(ii) Number of marble with number 5 on it = 1

therefore Probability of getting a marble with number 5

=number of favourable outcomes

= number of possible outcomes

$\implies{\boxed{\tt \red{\frac{1}{6}}}}$

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