There are six multiple choice questions in the examination. How many sequences of anwers are possible, if the first two
question have 3 choices each, the next two have 4 choice each and last two have 5 choices each?
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0
Answer:
permutationoffirstthreequestions=43=64Permutationofnextthreequestions=23=8∴totalpermutation=64×8=512
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Answer:
512 is correct answer
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