Question

there are six slips in a box & numbers 1,1,2,2,3,3 are written on these slips. two slips are taken at random from the box. the expected values of numbers on the two slips is:

Answer 1

(1,1) (1,2) (1,3)
(2,1) (2,2) (2,3)
(3,1) (3,2) (3,3)

Answer 2

Answer:

4

Step-by-step explanation:

Look at all of the possible outcomes, 15 of them,

(1,1)(1,2)(1,2)(1,3)(1,3)

(2,1)(2,1)(2,2)(2,3)(2,3)

(3,1)(3,1)(3,2)(3,2)(3,3)

and their sums,

2,3,3,4,4

3,3,4,5,5

4,4,5,5,6

So then look at the frequency of each sum,

2 appears once

3 appears 4 times

4 appears 5 times

5 appears 4 times

6 appears once

Then the probabilities would be,

2→ 1/15

3→ 4/15

4→ 5/15

5→ 4/15

6→ 1/15

Expected value: 2(1/15) + 3(4/15) + 4(5/15) + 5(4/15) + 6(1/15)

= 2/15+12/15+20/15+20/15+6/15

= 60/15

= 4

I hope it helps