There Are Some 25 paise coins and some 50 paise coins in bag.The total number of coins is 100 and the amount in bag is rupees 42.50 .Find the number of coins of each value in bag .Solve by Elimination method.
Answers
Step-by-step explanation:
The number of 50 paise of the coins are 14 and 25 paise of the coins are 16 .
Step-by-step explanation:
Let us assume that the 50 paise of the coins are x .
Let us assume that the 25 paise of the coins are y .
As given
There are some 50 paise and some 25 paise coins in a bag.
If the total number of coins 30 and their total value is ₹11 .
Equation becomes
x + y = 30
As
1 Rupee = 100 paise
1 Paise = 0.01 Rupee
For 50 paise
50 Paise = 50 × 0.01 Rupee
= 0.5 Rupee
25 Paise = 25 × 0.01 Rupee
= 0.25 Rupee
Equation becomes
0.5x + 0.25y = 11
Two equation becomes
x + y = 30
0.5x + 0.25y = 11
Multiply x + y = 30 by 0.5 and subtracted from 0.5x + 0.25y = 11 .
0.5x - 0.5x + 0.25y - 0.5y = 11 - 15
-0.25y = -4
0.25y = 4
y = {4}/{0.25}
y= 4/0.25
y = 16
Put the value of y in the equation x + y = 30 .
x + 16 = 30
x = 30 - 16
x = 14
Therefore the number of 50 paise of the coins are 14 and 25 paise of the coins are 16 .