there are some 50 paise and 25 paise coins in the bag. if the total coins are 25 and the value is rs 8.50, find the no of coins of each kind.
Answers
Answer:
The number of 50 paise of the coins are 14 and 25 paise of the coins are 16 .
Step-by-step explanation:
Let us assume that the 50 paise of the coins are x .
Let us assume that the 25 paise of the coins are y .
As given
There are some 50 paise and some 25 paise coins in a bag.
If the total number of coins 30 and their total value is ₹11 .
Equation becomes
x + y = 30
As
1 Rupee = 100 paise
1 Paise = 0.01 Rupee
For 50 paise
50 Paise = 50 × 0.01 Rupee
= 0.5 Rupee
25 Paise = 25 × 0.01 Rupee
= 0.25 Rupee
Equation becomes
0.5x + 0.25y = 11
Two equation becomes
x + y = 30
0.5x + 0.25y = 11
Multiply x + y = 30 by 0.5 and subtracted from 0.5x + 0.25y = 11 .
0.5x - 0.5x + 0.25y - 0.5y = 11 - 15
-0.25y = -4
0.25y = 4
y = \frac{4}{0.25}y=
0.25
4
y = 16
Put the value of y in the equation x + y = 30 .
x + 16 = 30
x = 30 - 16
x = 14
Therefore the number of 50 paise of the coins are 14 and 25 paise of the coins are 16 The number of 50 paise of the coins are 14 and 25 paise of the coins are 16 .
Step-by-step explanation:
Let us assume that the 50 paise of the coins are x .
Let us assume that the 25 paise of the coins are y .
As given
There are some 50 paise and some 25 paise coins in a bag.
If the total number of coins 30 and their total value is ₹11 .
Equation becomes
x + y = 30
As
1 Rupee = 100 paise
1 Paise = 0.01 Rupee
For 50 paise
50 Paise = 50 × 0.01 Rupee
= 0.5 Rupee
25 Paise = 25 × 0.01 Rupee
= 0.25 Rupee
Equation becomes
0.5x + 0.25y = 11
Two equation becomes
x + y = 30
0.5x + 0.25y = 11
Multiply x + y = 30 by 0.5 and subtracted from 0.5x + 0.25y = 11 .
0.5x - 0.5x + 0.25y - 0.5y = 11 - 15
-0.25y = -4
0.25y = 4
y = \frac{4}{0.25}y=
0.25
4
y = 16
Put the value of y in the equation x + y = 30 .
x + 16 = 30
x = 30 - 16
x = 14
Therefore the number of 50 paise of the coins are 14 and 25 paise of the coins are 16 The number of 50 paise of the coins are 14 and 25 paise of the coins are 16 .
Step-by-step explanation:
Let us assume that the 50 paise of the coins are x .
Let us assume that the 25 paise of the coins are y .
As given
There are some 50 paise and some 25 paise coins in a bag.
If the total number of coins 30 and their total value is ₹11 .
Equation becomes
x + y = 30
As
1 Rupee = 100 paise
1 Paise = 0.01 Rupee
For 50 paise
50 Paise = 50 × 0.01 Rupee
= 0.5 Rupee
25 Paise = 25 × 0.01 Rupee
= 0.25 Rupee
Equation becomes
0.5x + 0.25y = 11
Two equation becomes
x + y = 30
0.5x + 0.25y = 11
Multiply x + y = 30 by 0.5 and subtracted from 0.5x + 0.25y = 11 .
0.5x - 0.5x + 0.25y - 0.5y = 11 - 15
-0.25y = -4
0.25y = 4
y = \frac{4}{0.25}y=
0.25
4
y = 16
Put the value of y in the equation x + y = 30 .
x + 16 = 30
x = 30 - 16
x = 14
Therefore the number of 50 paise of the coins are 14 and 25 paise of the coins are 16 .