Question

There are some 50p and some 25p coins in a bag if the total no. of coins is 30and their total value is rupees 11.find the number of coins of each kind.​

Answer 1

Step-by-step explanation:

Given:-

• There are some 50p and 25p coins in the bag.

• The total number of coins = 30.

• The total amount = Rs.11

To Find:-

• The number of coins of each kind.

Solution:-

Let the number of 50p coins be x

And the number of 25p coins be y

Condition 1:-

The total number of coins = 30

$\sf \implies x + y = 30.....(ii)$

Condition 2:-

The total amount = Rs.11 = 1100p

$\sf\implies 50x + 25y = 1100$

Dividing the whole equation by 25

$\sf\implies 2x + y = 44.....(ii)$

Equation (ii) - (i):-

$\sf\implies 2x + y - (x + y) = 44 - 30$

$\sf \implies 2x + y - x - y = 14$

$\sf \implies x = 14$

Substitute x = 14 in equation (i)

$\sf \implies x + y = 30$

$\sf \implies 14 + y = 30$

$\sf \implies y = 30 - 14$

$\sf \implies y = 16$

Therefore:-

The number of 50p coins = 14

The number of 25p coins = 16

Answer 2

$\large\bf\underline{question:}$

There are some 50p and some 25p coins in a bag if the total no. of coins is 30and their total value is rupees 11.find the number of coins of each kind.

$\large\bf\underline{to\:find:}$

the number of coins of each kind

$\large\bf\underline{solution:}$

Let the number of 50 paise coin be "x"

Number of 25 paise coin will be 30-x

$\tt\underline\red{according\:to\: question:}$

$➞50x + 25(30 - x) = rs.11 = 1100 \: paise$

$➞50x + 750 - 25x = 1100$

$➞25x = 1100 - 750$

$➞25x = 350$

➞$\tt\underline\red{x\:=\:14}$

now let "y" be the number of coins of 25 paise:

$➞30 - x = y$

$➞y = 30 - 14$

➞$\tt\underline\red{ y = 16}$

$\large\bf\underline{hence:}$

• the number of 50 paise coins in 14 and,
• the number of 25 paise coin is 16