Math, asked by snehaanjali1306, 10 months ago

There are some
chocolates in a box. Frazer grabs 4/5 of the
lates and eats them. There are now 7 chocolates left in
Box. How many were in the box at the start?
Please answer as fast as you can. ​

Answers

Answered by krishshazia
7

Step-by-step explanation:

35is the answer to the question

Answered by sanjeevk28012
7

Total number of chocolates initial in the box is 35

Step-by-step explanation:

Given as :

Let The number of chocolates in the box =  n

The number of chocolates grab by Frazer = \dfrac{4}{5} of total

i.e number of chocolates grab by Frazer = \dfrac{4}{5} × n

Number of chocolates left in box = 7

According to question

Total number of chocolates in box - number of chocolates grab by Frazer = number of chocolates left in box

i.e  n - \dfrac{4}{5} × n  = 7

Or,  n - \dfrac{4n}{5}  = 7

Or,  \dfrac{5 n - 4n}{5} = 7

or,  \dfrac{n}{5} = 7

By cross multiplication

∴   n = 5 × 7

i.e  n = 35

So, Total number of chocolates initial in the box = n = 35

Hence, Total number of chocolates initial in the box is 35  Answer

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