There are some five rupees and ten rupees coins in raman hand. One five rupees coin higher than ten rupees coin. If the sum of the coins he have rupees 80. Then how many coins did he have in each category?
Solve it anyone?
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Answer:
11
Step-by-step explanation:
if there are x coins of 10 rupees , then there will be (× +1) coins of 5 rupees as given in the question.
now
( x + 1 )5 + 10x = 80
5x + 5 +10x = 80
15x = 80 - 5
15x = 75
x = 75/15
x = 5
so number of 10 rupee coin = 5
and 5 rupee coin = 5+1 = 6
total coin = 5+6=11
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