there are some hens and cows in a form if the number of heads is 50 and the number of legs is 144 then find the number of hens in the farm
Answers
Answered by
6
let the no. of hens be x and no. of cows be y. For heads the equation is
x + y = 50 (head count is 50)
For legs the equation is
2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs)
From head count equation
y = 50 - x
substituting this in leg count equation we get
2x + 4(50 - x) = 144
2x + 200 - 4x = 144
-2x = 144 - 200
-2x = - 56
x = 28
Substituting in headcount equation we get
y = 50 - 28
So y = 22
x + y = 50 (head count is 50)
For legs the equation is
2x + 4y =144 (2 legs of hen and 4 legs of cow assuming that none are missing any limbs)
From head count equation
y = 50 - x
substituting this in leg count equation we get
2x + 4(50 - x) = 144
2x + 200 - 4x = 144
-2x = 144 - 200
-2x = - 56
x = 28
Substituting in headcount equation we get
y = 50 - 28
So y = 22
anesha633:
hotty alisha k bf hain na tu
Similar questions