there are the three consecutive even integers. let x be the smallest one.
express the other two integers in terms of X
if the sum of these three integers is 66, find the integers
Answers
Answered by
3
Step-by-step explanation:
Take the first integer as
x
. Since we are talking about the next even integer, it will come when you add two to
x
.
For example, let's say that you have
2
as the value of
x
. The next even integer is
4
, which is
x
+
2
, and the next is
6
, which is
x
+
4
.
So eventually, the equation is
(
x
)
+
(
x
+
2
)
+
(
x
+
4
)
=
66
3
x
+
6
=
66
3
x
=
66
−
6
3
x
=
60
x
=
60
÷
3
x
=
20
So
x
=
20
x
+
2
=
22
x
+
4
=
24
Answered by
1
Answer:
let the three integers be X,X+1,X+2
now we have X+X+1+X+2=66
3x+3=66
X+3=66÷3
X+3=22
X=22-3
X=19
Hence ,the three numbers are 19,20,21
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