There are thirteen 2-digit consecutive odd numbers. If 39 is the mean of the first live such numbers, then what is the mean of all the thirteen numbers?
Answers
Answered by
5
Answer:
49
Step-by-step explanation:
let one of the no.s is x
take the 1st 5 no.s as x, x+1, x+2, x+3 and x+4.
mean of the no.s =39(in question)
(x+x+1+ x+2+x+3+x+4)/5=39
(5x+10)/5=39
5(x+2)=39×5
x+2=39
x=37
so the 13 nos are: 37 39 41 43 45 47 49 51 53 55 57 59 and 61.
their mean:
(37 +39+ 41 +43 +45 +47 +49+ 51 53 +55+ 57 +59 +61)/13=47
#PLS FOLLOW ME!!!
Answered by
4
Answer: 47
Step-by-step explanation:
let one of the no.s is x
take the 1st 5 no.s as x, x+2, x+4, x+5 and x+8(since consecutive but odd...difference has to be 2)
mean of the no.s =39(in question)
(x+x+2+ x+4+x+6+x+8)/5=39
(5x+20)/5=39
5(x+4)=39×5
x+4=39
x=35
so the 13 nos are: 35 37 39 41 43 45 47 49 51 53 55 57 and 59.
their mean:
(35+37 +39+ 41 +43 +45 +47 +49+ 51 53 +55+ 57 +59 )/13=47
Similar questions