Question

There are three angles. The second angle is one third of the complement of the first angle. The third angle is half of the supplement of the first angle. The third angle is 6 times the second angle. Find the first angle.

Answer 1

$\huge{\mathfrak\red{Question}}$

There are three angles. The second angle is one third of the complement of the first angle. The third angle is half of the supplement of the first angle. The third angle is 6 times the second angle. Find the first angle.

$\huge{\mathfrak\blue{Answer}}$

Let us assume the first, second and third angle to be B,S and T.

$S= \frac{90 - f}{3} = \frac{30 - f}{3}$

$T= \frac{180 - f}{2} = 90 - (f)(2)$

$\therefore 90° - \frac{f}{2} \\ = 6(30 - \frac{f}{3} )$

$\implies \: 90 - \frac{f}{2} = 180 - 2f$

$</p><p>\therefore{\mathfrak\pink{First \: angle= 60°}} </p><p>$

Khadijah21

Answer 2

Answer:

Question

There are three angles. The second angle is one third of the complement of the first angle. The third angle is half of the supplement of the first angle. The third angle is 6 times the second angle. Find the first angle.

\huge{\mathfrak\blue{Answer}}Answer

Let us assume the first, second and third angle to be B,S and T.

S= \frac{90 - f}{3} = \frac{30 - f}{3}S=

3

90−f

=

3

30−f

T= \frac{180 - f}{2} = 90 - (f)(2)T=

2

180−f

=90−(f)(2)

\begin{gathered}\therefore 90° - \frac{f}{2} \\ = 6(30 - \frac{f}{3} )\end{gathered}

∴90°−

2

f

=6(30−

3

f

)

\implies \: 90 - \frac{f}{2} = 180 - 2f⟹90−

2

f

=180−2f

< /p > < p > \therefore{\mathfrak\pink{First \: angle= 60°}} < /p > < p ></p><p>∴Firstangle=60°</p><p>

Step-by-step explanation:

Please mark me as brainliest answer

Purple you Army❤❤❤