Question

There are three bags, the first bag contains 3 red ball, 3 white ball and 2 black balls, the second bag contains 2 red ball, 3 white ball and 3 Black balls, the third bag contains 4 red, 3 white and 1 black balls. A person draw randomnly three balls from any of the bag, find the probability of getting. 1) All three balls are of same colour. 2) All three balls are of different colour. 3) Two balls are of same colour and one is different​

Answer 1

Answer:

5/28

Step-by-step explanation:

Probability of not getting red ball in first draw =  8/6

Probability of not getting red ball in second draw =  5/7

And probability of getting red ball in third draw =  6/2

Hence required probability =  

8/6  ×  7/5×  6/2  =  5/28

Hope It Helps !!!