Math, asked by mani6294621047, 10 days ago

There are three boxes. The first box contains 10 red balls, the second box contains 10 blue balls, and the third box contains 5 red and 5 blue balls. The boxes are wrongly labelled as red, blue and red-blue. You have to correctly lable each box. You are allowed to open one box, pick one ball at random, see its colour and put it back into the box, without seeing the color of the other balls. What is the smallest number of such operations necessary to correctly label the boxes ? (A) 1 (B) 2 (C) 3 (D) 4

Answers

Answered by ayeshazafar594
0

Answer:

(A) 1

Step-by-step explanation:

Bcz There are 3 boxes red, blue and red-blue. The 1 label must be correct.

It may be red or blue or red-blue.

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