There are three boys and two girl .A committee of two is to be formed. Find the probability of the events that the committe contain (a) at least one girl and (b)only boys.
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a. Let A = Event of forming a committee which contains atleast one girl
A = { B1G1, B1G2, B2G1, B2G2, B3G1, B3G2, G1G2}
n(A) = 7
P(A)=n(A)/ n(S)=7 / 10
b. Let B = Event that the committee contains one boy and one girl.B = { B1G1, B1G2, B2G1, B2G2, B3G1, B3G2, }
∴ n(B) = 6
P(B)=n(B) / n(S)=6/10 =3/5
A = { B1G1, B1G2, B2G1, B2G2, B3G1, B3G2, G1G2}
n(A) = 7
P(A)=n(A)/ n(S)=7 / 10
b. Let B = Event that the committee contains one boy and one girl.B = { B1G1, B1G2, B2G1, B2G2, B3G1, B3G2, }
∴ n(B) = 6
P(B)=n(B) / n(S)=6/10 =3/5
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