Math, asked by govarshini123, 1 month ago

There are three brands of milk available for sale in a city - brand A, brand B and brand C. In a
town of 10000 families, it was found that 40% families buy brand A, 20% buy brand B and 10%
buy brand C. Also 5% families buy brands A and B, 3% buy B and C and 4% buy A and C. 2%
families buy all the three brands.

Based on the above information answer the following :


i. Number of families which buy the milk of brand A only, is

(a) 3030 (b) 3300 (c) 3003 (d) 4500


ii. Number of families which buy the milk of exactly two brands, are

(a) 600 (b) 990 (c) 60 (d) 6000


iii. What is the number of families which buy the milk of exactly one brand?

(a) 2500 (b) 5020 (c) 5200 (d) 2000


iv. Number of families which buy the milk of brands A and C but not B is

(a) 20 (b) 2000 (c) 400 (d) 200


v. What is the number of families which buy the milk of brands of at least one of A, B, C?

(a) 990 (b) 6000 (c) 9000 (d) 3000

class11 maths​

Answers

Answered by RvChaudharY50
29

Given :- There are three brands of milk available for sale in a city - brand A, brand B and brand C. In a town of 10000 families, it was found that 40% families buy brand A, 20% buy brand B and 10% buy brand C. Also 5% families buy brands A and B, 3% buy B and C and 4% buy A and C. 2% families buy all the three brands.

Based on the above information answer the following :

Solution :-

Total families = 10000

so,

→ Families buy brand A = (40 * 10000)/100 = 4000

→ Families buy brand A = (20 * 10000)/100 = 2000

→ Families buy brand C = (10 * 10000)/100 = 1000

→ Families buy brand A and B = (5 * 10000)/100 = 500

→ Families buy brand B and C = (3 * 10000)/100 = 300

→ Families buy brand A and C = (4 * 10000)/100 = 400

→ Families buy brand all three brands = (2 * 10000)/100 = 200

then,

i. Number of families which buy the milk of brand A only, is

(a) 3030 (b) 3300 (c) 3003 (d) 4500

→ Familes buy milk of brand A only = Families buy brand A - Families buy brand A and B - Families buy brand A and C + Families buy brand all three brands = 4000 - 500 - 400 + 200 = 4000 - 700 = 3300 (b)

ii. Number of families which buy the milk of exactly two brands, are

(a) 600 (b) 990 (c) 60 (d) 6000

→ Number of families which buy the milk of exactly two brands = 500 + 300 + 400 - 3 * 200 = 600 (a)

iii. What is the number of families which buy the milk of exactly one brand?

(a) 2500 (b) 5020 (c) 5200 (d) 2000

→ The number of families which buy the milk of exactly one brand = 6000 - (500 + 300 + 400 - 2 * 200) = 5200 (c)

iv. Number of families which buy the milk of brands A and C but not B is

(a) 20 (b) 2000 (c) 400 (d) 200

→ Families buy brand A and C = 400 (c)

v. What is the number of families which buy the milk of brands of at least one of A, B, C ?

(a) 990 (b) 6000 (c) 9000 (d) 3000

→ The number of families which buy the milk of brands of at least one of A, B, C = 4000 + 2000 + 1000 - 500 - 300 - 400 + 200 = 6000 (b)

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