There are three brands of milk available for sale in a city - brand A, brand B and brand C. In a
town of 10000 families, it was found that 40% families buy brand A, 20% buy brand B and 10%
buy brand C. Also 5% families buy brands A and B, 3% buy B and C and 4% buy A and C. 2%
families buy all the three brands.
Based on the above information answer the following :
i. Number of families which buy the milk of brand A only, is
(a) 3030 (b) 3300 (c) 3003 (d) 4500
ii. Number of families which buy the milk of exactly two brands, are
(a) 600 (b) 990 (c) 60 (d) 6000
iii. What is the number of families which buy the milk of exactly one brand?
(a) 2500 (b) 5020 (c) 5200 (d) 2000
iv. Number of families which buy the milk of brands A and C but not B is
(a) 20 (b) 2000 (c) 400 (d) 200
v. What is the number of families which buy the milk of brands of at least one of A, B, C?
(a) 990 (b) 6000 (c) 9000 (d) 3000
class11 maths
Answers
Given :- There are three brands of milk available for sale in a city - brand A, brand B and brand C. In a town of 10000 families, it was found that 40% families buy brand A, 20% buy brand B and 10% buy brand C. Also 5% families buy brands A and B, 3% buy B and C and 4% buy A and C. 2% families buy all the three brands.
Based on the above information answer the following :
Solution :-
→ Total families = 10000
so,
→ Families buy brand A = (40 * 10000)/100 = 4000
→ Families buy brand A = (20 * 10000)/100 = 2000
→ Families buy brand C = (10 * 10000)/100 = 1000
→ Families buy brand A and B = (5 * 10000)/100 = 500
→ Families buy brand B and C = (3 * 10000)/100 = 300
→ Families buy brand A and C = (4 * 10000)/100 = 400
→ Families buy brand all three brands = (2 * 10000)/100 = 200
then,
i. Number of families which buy the milk of brand A only, is
(a) 3030 (b) 3300 (c) 3003 (d) 4500
→ Familes buy milk of brand A only = Families buy brand A - Families buy brand A and B - Families buy brand A and C + Families buy brand all three brands = 4000 - 500 - 400 + 200 = 4000 - 700 = 3300 (b)
ii. Number of families which buy the milk of exactly two brands, are
(a) 600 (b) 990 (c) 60 (d) 6000
→ Number of families which buy the milk of exactly two brands = 500 + 300 + 400 - 3 * 200 = 600 (a)
iii. What is the number of families which buy the milk of exactly one brand?
(a) 2500 (b) 5020 (c) 5200 (d) 2000
→ The number of families which buy the milk of exactly one brand = 6000 - (500 + 300 + 400 - 2 * 200) = 5200 (c)
iv. Number of families which buy the milk of brands A and C but not B is
(a) 20 (b) 2000 (c) 400 (d) 200
→ Families buy brand A and C = 400 (c)
v. What is the number of families which buy the milk of brands of at least one of A, B, C ?
(a) 990 (b) 6000 (c) 9000 (d) 3000
→ The number of families which buy the milk of brands of at least one of A, B, C = 4000 + 2000 + 1000 - 500 - 300 - 400 + 200 = 6000 (b)
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