there are three brothers named rohan ,abhishek,ram.If age of rohan is 4times the age of abhishek's age and age of abhishek is one third of ram 's age.Sum of their ages add upto 21 years.Find the exact age of everybody.
Answers
Answered by
1
Solution:
Let, ram's age=x
Therefore, abhisek's age=1/3 ×ram's age
=1/3x
And, rohan's age=4× abhisek's age
=4×1/3x
=4/3x
A/Q,
Rohan's age+abhisek's age+ram's age=21
=>4/3x+1/3x+x=21
=>4x+1x+3x/3=21
=>8x=21×3
=>x=63/8
Hence,ram's age=63/8
Abhisek's age=1/3×63/8
=21/8
Rohan's age=4×21/8
=21/2
Let, ram's age=x
Therefore, abhisek's age=1/3 ×ram's age
=1/3x
And, rohan's age=4× abhisek's age
=4×1/3x
=4/3x
A/Q,
Rohan's age+abhisek's age+ram's age=21
=>4/3x+1/3x+x=21
=>4x+1x+3x/3=21
=>8x=21×3
=>x=63/8
Hence,ram's age=63/8
Abhisek's age=1/3×63/8
=21/8
Rohan's age=4×21/8
=21/2
Chaitanya1341:
your answer is correct but you didn t calculate the age of ram in years,days, or months
you have to do it because someone's age cannot be in fractions,can it be?
Then divide. It's true we can't write age in fraction, but writing in fraction is acceptable.
Similar questions