Question

There are three buckets X Y and Z. X contains a mixture of liquids A and B in the ratio 32. Y contams a
mixture of liquids B and C m the ratio 5:3 and Z contains a mixture of liquids A and C in the ratio 2: 3.
Now 2 frters of mixture from X 4 liters of mixture from Y and 2 liters of mixture from Z are mixed in a new
bucket. If one Iner of this new mixture is taken out, the amount of A it will be-
​

Answer 1

Given :-

• in bucket X liquid A : B = 3 : 2.
• in bucket Y liquid A : B = 5 : 3.
• in bucket Z liquid A : B = 2 : 3.
• 2 Litre of mixture from X , 4 liters of mixture from Y and 2 liters of mixture from Z are mixed in a new
• bucket.

To Find :-

• If one litre of this new mixture is taken out, the amount of A in it will be ?

Solution :-

in 2 litre of mixture X :-

• A = 2 * (3/5) = (6/5) litre.
• B = 2 * (2/5) = (4/5) litre.

in 4 litre of mixture Y :-

• A = 4 * (5/8) = (5/2) litre.
• B = 4 * (3/8) = (3/2) litre.

in 2 litre of mixture Z :-

• A = 2 * (2/5) = (4/5) litre.
• B = 2 * (3/5) = (6/5) litre.

then , in bucket :-

• Quantity of A = (6/5) + (5/2) + (4/5) = (9/2)
• Quantity of B = (4/5) + (3/2) + (6/5) = (7/2)

therefore, in new bucket :-

• A : B = (9/2) : (7/2) = 9 : 7 .

hence, in 1 litre of new mixture from new bucket ,

• Amount of A = 1 * (9/16) = (9/16) litre. (Ans.)

∴ The amount of A in new bucket will be (9/16) litre.

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Answer 2

Answer:

250ML

Step-by-step explanation:

x, 2L

A:B= 3:2

A=(3/3+2) =6/5

B=4/5

z. 2L=8L

A:C=2:3

A=6/5+4/5=10/5=2L

2/8*100=250ML