Question

There are three charges 2q + 3Q, 5q - 6Q, 7q - 7Q, which are enclosed by the surface S. What is the net flux crosses surface S.

Answer 1

Answer 14q+2Q/eo

Explanation:

flux through a surface is q enclosed/eo

q enclosed = 14q+2Q

Hope I was of some help

Answer 2

Answer :

Three charges 2q + 3Q, 5q - 6Q, 7q - 7Q are enclosed by the surface S.

We have to find the net flux associated with the surface S$.$

◈ According to Gauss's theorem, the total electric flux through a closed surface S enclosing charge Σq is given by

• Φ = Σq / ε°

፨ Φ denotes flux

፨ Σq denotes net enclosing charge

፨ ε° denoted permittivity

» Σq = (2q+3Q) + (5q-6Q) + (7q-7Q)

» Σq = (2q+5q+7q) + (3Q-6Q-7Q)

» Σq = 14q - 10Q

⟶ Φ = Σq / ε°

⟶ Φ = (14q - 10Q) / ε°

⟶ Φ = 2(7q - 5Q) / ε°

☃ God_Bless :)