There are three charges, q1 = q2 = q3 = 1C. Their position vectors are respectively (0, 0, 0)m, (1, 0, 0)m and (0, 1, 0)m. So the force acting on q1 is..?
Answers
Explanation:
Position vectors of two point charges of 1nC each are (1,1, - 1) m and (2,3,1) m respectively. Magnitude of electric force acting between them is N.
Given info : There are three charges, q1 = q2 = q3 = 1 C. Their position vectors are (0, 0, 0) , (1, 0, 0) and (0, 1, 0) respectively.
To find : The force acting on q1 is ...
solution : see diagram,
force exerted by q3 on q1 = kq1q3/r²
= (9 × 10^9 × 1 × 1)/(1)² = 9 × 10^9 N along negative y - axis.
force exerted by q2 on q1 = kq1q2/r²
= (9 × 10^9 × 1 × 1)/(1)² = 9 × 10^9 N along negative x axis.
now net force = 9 × 10^9 [-i - j]
magnitude of force acting on q1 = 9 × 10^9 × √(1² + 1²) = 9√2 × 10^9 N
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