Question

there are three consecutive integer such that the square of the first increased by the product of the other two gives 154 what are the integers

Answer 1

Answer:

the numbers are 8,9,10

Step-by-step explanation:

let the numbers be :

(x-1),x,(x+1)

according to the question,

(x-1)²+x(x+1)=154

simplifying,

x²-2x+1+x²+x=154

2x²-x=154-1

2x²-x-153=0

using equation x=(-b√(b²-4ac))/(2a)

we get,

x=(1±√(1-(4x2x-153))/4

x=(1±√1225)/4

x=9 or -8.5

they are integers .. so it is 9

so, the numbers are

8,9,10