There are three consecutive integers. The sum of the first two is 35 more than the third. Find the integers.
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Three consecutive integers can be written as (x),(x+1),(x+2)
Adding them:
(x)+(x+1)+(x+2)=75
3x+3=75
3x=75−3=72
x=723=24
so ,x+1=25,x+2=26
The numbers are 24,25,26 .
HOPE IT HELPS
Adding them:
(x)+(x+1)+(x+2)=75
3x+3=75
3x=75−3=72
x=723=24
so ,x+1=25,x+2=26
The numbers are 24,25,26 .
HOPE IT HELPS
huiminhuang37:
Thank You!
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