Question

There are three consecutive integers. The sum of the first two is 35 more than the third. Find the integers.

Answer 1

35+x+2=x+x+1 
37+x=2x+1 
-x -x 
___________ 
37=x+1 
-1 -1 
__________ 
x=36 
hope it helps!!

Answer 2

The integers are 36 , 37 and 38

Step-by-step explanation:

Let the three consecutive integers be x ,x+1,x+2

The sum of the first two is 35 more than the third.

So, x+x+1=x+2+35

2x+1=x+37

2x-x=37-1

x=36

So, x = 36

x+1=36+1=37

x+2=36+2=38

Hence the integers are 36 , 37 and 38

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