Math, asked by faruuqmaxamed1190, 1 year ago

there are three consecutive positive integers such that the sum of the square of the first and product of other two is 191 what are the integers

Answers

Answered by hemanth2261
13
let the three consecutive positive numbers be x+1, x+2, x+3 say
according to the problem
(x+1)^2+(x+2)(x+3)=191
x^2+2x+1+x^2+3x+2x+6=191
2x^2+7x+7-191=0
2x^2+7x-184=0
2x^2+23x-16x-184=0
x(2x+23)-8(2x+23)=0
(2x+23)(x-8)=0
x=-23/2
or
x=8
Answered by shivyakikloo
0

Answer:

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