Question

There are three digits A, B and C. When 1/3 of B is added to A and subtracted from C, all the digits become same. What is the value of A and C respectively.

Answer 1

Given:

1/3 of B is added to A and subtracted from C, all the digits become the same.

To find:

The value of A and C.

Solution:

We have three numbers A, B, and C

According to the condition:

A+1/3 of B = B = C-1/3 of B

Case1:

• A+1/3 of B = B
• A+B/3 = B
• A = B-B/3
• A = 2B/3
• A/B = 2/3---------------(I)

Case2:

• B = C-1/3 of B
• B = C-B/3
• C = B+B/3
• C = 4B/3
• C/B = 4/3--------------(II)

from equation (I) and (II) we get

• A:B:C = 2:3:4

and A:C = 2:4 (better to not simplify it as this will affect the B also)

As this is the ratio, so answer may vary

The value of A and C is 2 and 4 or the multiple of it.