There are three families A, B and C. Family A has 2 men, 4 women and 3 children. Family B has 3 men, 3 women and 2 children. Family C has 2 men, 2 women and 5 children. A man earns 500 per day and spends 300 per day. A woman earns * 400 per day and spends * 250 per day. A child spends *40 per day. Find the money each family saves per day using matrices.
Answers
Answered by
1
Answer:
family a =>
men = 500× 2 - 300 × 2 = 400
women = 400 × 4 - 250 × 4 = 600
children = - 60 × 3 = 120
total saving of family a = 600 + 400 - 120 = 880 rs
family b =>
men = 500 × 3 - 300 × 3 = 600 rs
women = 3 × 400 = 1200 - 250 × 3 = 550 rs
children = 5 × - 40 = - 200
total saving = 600 + 550 - 200 = 950 rs
family c =
men = 2 × 500 = 1000 - 300 × 2 = 400rs
women = 400 × 2 - 250 × 2 = 300 rs
children = - 40 × 5 = - 200
total saving = 400 + 300 - 200 = 500 rs
therefore, total savings of three families are --
FAMILY a = 880 rs
FAMILY B = 950 rs
FAMILY C = 500 rs
very interesting question
PLEASE MARK AS BRAINLIEST
MY DEAR BROTHER OR SISTER
Similar questions