There are three geometrical means between a and b. If the first and the third means are 25 and 125 respectively, find a and b.
Answers
Answer:
The geometric mean is a geometric series which is in the form of arn where a is the first term and r is the common ratio.
T1= 5 and T5 = 3125
Now, T1/T5 = 5/ 3125
=>ar1//ar5 =1/ 625
=> 1/ r4 = 1/625
=> r4 = 625
=> r = 5
So if r=5, then a= 1
T2 = ar2
= 1(5) 2 = 25
T3 = ar3
= 1(5) 3 = 125
T4 = ar4
= 1(5)4 = 625
Therefore, three geometric means between 5 and 3125 are 25, 125 and 625
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Answer:
The geometric mean is a geometric series which is in the form of arn where a is the first term and r is the common ratio.
T1= 5 and T5 = 3125
Now, T1/T5 = 5/ 3125
=>ar1//ar5 =1/ 625
=> 1/ r4 = 1/625
=> r4 = 625
=> r = 5
So if r=5, then a= 1
T2 = ar2
= 1(5) 2 = 25
T3 = ar3
= 1(5) 3 = 125
T4 = ar4
= 1(5)4 = 625
Therefore, three geometric means between 5 and 3125 are 25, 125 and 625
Help:
please mark me brainly list