There are three isotopes of carbon which are named as C-12, C-13 and C-14 out of which C-12 is the most abundant isotope. In the given structures of 3 isotopes, what will be the composition of the nucleus?
(a) C-12 : 6p + 6n, C-13 : 7p + 6n, C-14 : 8p + 6n
(b) C-12 : 6p + 6n, C-13 : 6p + 7n, C-14 : 6p + 8n
(c) C-12 : 6p + 6n, C-13 : 5p + 8n, C-14 : 7p + 7n
(d) C-12 : 6p + 6n, C-13 : 12p + 1n, C-14 : 5p + 9n
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Correct Answer: (b) C-12 : 6p + 6n, C-13 : 6p + 7n, C-14 : 6p + 8n
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C-12 is the most stable form of carbon isotope amongst its three isotopes
- The element carbon has three isotopes, C-12, C-13, and C-14. Isotopes are elements with a similar number of protons but a different number of neutrons belonging to the same family.
- The composition of all the three isotopes of C are as follows:
In C-12:
- Number of protons = 6
- Number of neutrons = 6
In C-13
- Number of protons = 6
- Number of neutrons = 7
In C-14
- Number of protons = 6
- Number of neutrons = 8
Thus, (Option b) C-12 : 6p + 6n, C-13 : 6p + 7n, C-14 : 6p + 8n is the correct answer for the given question.
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