Math, asked by aftaabmulla10, 1 month ago

there are three natural numbers such that the sum of first two numbers is 65the sum of last two numbers is 120 and the first and last number is 95 find the numbers​

Answers

Answered by rishibhardwaj57
1

Answer:

A = 20 ; B = 45 ; C = 75

Step-by-step explanation:

Let the three natural numbers be A, B, C.

According to the Question ;

A + B = 65 ------------ (1)

B = 65 - A ------------ (2)

A + C = 95 ------------ (3)

C = 95 - A ------------ (4)

B + C = 120 ---------- (5)

(65 - A) + (95 - A) = 120 [ From (2) & (4) ]

65 - A + 95 - A = 120

160 - 2A = 120

160 - 120 = 2A

2A = 40

A = 20 ---------- (6)

B = 65 - A [ From (2) ]

B = 65 - 20 [ From (6) ]

B = 45

C = 95 - A [ From (4) ]

C = 95 - 20 [ From (6) ]

C = 75

Hope it helps u !!!!!!!!!

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