There are three numbers.And I am not telling those numbers to you as usual.Now first number is twice the second number and it is also thrice the third number.If the average of the three numbers is 88.Find the largest number and which number it is furst, second or third
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Answer:
Let the first number be X. Now the second number would be 2X. If the second number is thrice the third number, the third number would be 2X/3. The average of the three numbers is 44, therefore the sum of these three numbers would be 44×3=132. Now we get the following equation.
X+2X+2X/3 =132
(3X+6X+2X)/3=132
11X/3=132
11X=132×3=396
X=396÷11=36
Therefore the numbers are
X=36
2X=72 and
2X/3=72/3=24
The first number is 36, the second number is 72 and the third number is 24. The highest number is the second number 72.
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pommi 's 2020 answer is correct,......same is the here.
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