there are three numbers the first and second numbers are 20 and 40% more than the third number what percentage is the first number of the sum of the second and the third number.
I need only soln
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let first number be x
second no. = X+20/100
Third no. =X+40/100
X=X+20×100/X+40/100
X=20
first no=20
second no=20×20/100=4+20=24
third no.=20×40/100=8+20=28
second no. = X+20/100
Third no. =X+40/100
X=X+20×100/X+40/100
X=20
first no=20
second no=20×20/100=4+20=24
third no.=20×40/100=8+20=28
Ashyo:
reread the question
re read question
hey
your answer is incorrect
I made u brainliast by mistake
Answered by
2
Hello friend!!!!
Please refer to the attachment for your answer.
HOPE IT HELPS...... :-)
Please refer to the attachment for your answer.
HOPE IT HELPS...... :-)
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sorry I wanted to make your answer brainliast but I made mistake
your solution is right
but u made mistake in adding 2nd and 3rd no.
anyway thanx for soln
its ok....no problem
it must have been 7x
sry
no problem but thanx for your response
:-)
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