There are three pillars x, y and z of different heights. three spiders a, b and c start to climb on these pillars simultaneously. in one chance, a climbs on x by 6 cm but slips down 1 cm. b climbs on y by 7 cm but slips down 3 cm. c climbs on z by 6.5 cm but slips down 2 cm. if each of them requires 40 chances to reach the top of the pillars, what is the height of the shortest pillar?
Answers
Answer:
The height of the shortest pillar is 163 cm.
For spider a; in 1 chance:
a climbs = 6 cm
a falls down by = 1 cm
So, in total a climbs = 6 cm – 1 cm = 5 cm
So, after 39th chance a manages to climb = 39 x 5cm = 195 cm
∴ In the 40th chance, a climbs in total = 195 cm + 6 cm = 201 cm = Height of pillar x.
For spider b; in 1 chance:
b climbs = 7 cm
b falls down by = 3 cm
So, in total b climbs = 7 cm – 3 cm = 4 cm
So, after 39th chance b manages to climb = 39 x 4 cm = 156 cm
∴ In the 40th chance, b climbs in total = 156 cm + 7 cm = 163 cm = Height of pillar y.
For spider c; in 1 chance:
c climbs = 6.5 cm
c falls down by = 2 cm
So, in total c climbs = 6.5 cm – 2 cm = 4.5 cm
So, after 39th chance c manages to climb = 39 x 4.5 cm = 175.5 cm
∴ In the 40th chance, c climbs in total = 175.5 cm + 6.5 cm = 182 cm = Height of pillar z.
Hence, Height of pillar x = 201 cm
Height of pillar y = 163 cm
Height of pillar z = 182 cm
∴ The height of the shortest pillar is pillar y = 163 cm.