Math, asked by Amanazy, 5 hours ago

There are three pipes, A, B and C, attached to container. A and B can fill the container alone in 20 and 30 mins, respectively whereas C can empty the container alone in 45 mins. The three pipes are kept opened alone for one minute each in the the order A, B and C. The same order is followed subsequently. In how many minutes will the reservoir be full?

I'll mark brainliest to the one who'll give the correct answer with explanation ​

Answers

Answered by mundrakol
0

Answer:

9.5 mins(approx)

Step-by-step explanation:

A alone = 20 mins

A in 1 min = 1/20 work

B alone = 30 mins

B in 1 min = 1/30 work

C alone = 45 mins

C in 1 min = 1/45 work

All the three in 1 min = 1/20+ 1/30 +1/45

= 9 + 6 + 4 / 180

= 19/180 work

19/180 work= 1 min

1/1 work = 180/19 mins

= 9.5 mins(approx)

Answered by Anonymous
5

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