There are three pipes, A, B and C, attached to container. A and B can fill the container alone in 20 and 30 mins, respectively whereas C can empty the container alone in 45 mins. The three pipes are kept opened alone for one minute each in the the order A, B and C. The same order is followed subsequently. In how many minutes will the reservoir be full?
I'll mark brainliest to the one who'll give the correct answer with explanation
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Answer:
9.5 mins(approx)
Step-by-step explanation:
A alone = 20 mins
A in 1 min = 1/20 work
B alone = 30 mins
B in 1 min = 1/30 work
C alone = 45 mins
C in 1 min = 1/45 work
All the three in 1 min = 1/20+ 1/30 +1/45
= 9 + 6 + 4 / 180
= 19/180 work
19/180 work= 1 min
1/1 work = 180/19 mins
= 9.5 mins(approx)
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