Question

There are three point charge of equal magnitude q placed at the three corner of a right angle triangle ,as shown in AB=AC what is the magnitude and direction of the force exerted on _q​

Answer 1

Answer:

incomplete question no figure is given

Answer 2

Answer:

GIVEN IN THE ATTACHMENT

Explanation:

Since the diagram was not given in the question so I assumed (-q) charge on point D.

HERE angle x = angle ACD (of triangle ACD)

Since AD is the perpendicular bisector for line BC. So its natural to get an angle bisector also for angle BAC = 90 degree

Hence, Angle DAC = 45 degree

THE ABOVE THING IS BEING DONE WITH THE MOTIVE TO PROVE THAT TRIANGLE ADC IS ISOSCELES AND WE GET

AD = DC

And we know that DC = a root2 / 2. By that we will get AD

Once we get AD we will easily take out the force by charge at A by the formula

F = K x q1 x q2 / r²

HOPE THIS HELPS YOU