Question

There are three points A. B and C at the corners of an equilateral triangle. There is a point-charge of +
0.100 u Cat A. What will be the intensity of electric field at the mid-point between B and C. if the side
of the triangle is 10.0 cm​

Answer 1

Answer:

12 × 10^4 N/C

Explanation:

electric field at mid point = kQ/r^2

charge is 0.100 micro coloumb

which is 100× 10^-9

joining A and midpoint of B and C we get a right angled triangle

using Pythagoras theorem

100 = 25+ x^2

x = 5√3 cm

now by solving

9×10^9 × 100 × 10^-9 × 10^4 / 25×3

=12 × 10^4 N/C

Hope I was able to solve your doubt