Question

There are three positive numbers- A,B and C. Number B is 75% of number A and
the respective ratio between the sum of numbers A and B and the number C is
14:5. Number A is what percent more than number C?​

Answer 1

Answer:

I can't answer this question because I have not any ideas about this

Step-by-step explanation:

I can't answer this question because I have not any ideas about this

Answer 2

Number A is 37.5% more than number C.

Step-by-step explanation:

Let the number A be 'x'

Let the number B be

$\dfrac{75}{100}\times x\\\\=\dfrac{3}{4}x$

Ratio of sum of numbers A and B and the number C = 14:5

So, it becomes

$\dfrac{A+B}{C}=\dfrac{x+\dfrac{3}{4}x}{C}=\dfrac{14}{5}\\\\\dfrac{7x}{4C}=\dfrac{14}{5}\\\\\dfrac{x}{4C}=\dfrac{2}{5}\\\\C=\dfrac{5x}{8}$

Difference between A and C would be

$x-\dfrac{5x}{8}\\\\=\dfrac{8x-5x}{8}\\\\=\dfrac{3x}{8}$

So, Number A is more than number C by

$\dfrac{3x}{8x}\times 100\\\\=\dfrac{300}{8}\\\\=37.5\%$

Hence, Number A is 37.5% more than number C.

# learn more:

If 75% of a number is added to 75, then the result is the number itself. The number is :

A) 100

B) 200

C) 300

D) 400

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