Math, asked by dh5112608gmailcom, 5 months ago

There are three prizes for 10 constables. In how many ways it can be awarded to them if a person don't get more than one prize?​

Answers

Answered by shravan7294
0

Answer:

in first group 3 people

in second group 3 people

and in last group 4 people

Answered by Rupma
2

Total number of students=5

Total number of prizes =3

Condition that no stdent gets more than one prize

Number of possible ways

=

 \frac{10}{} c \frac{}{3}

 \frac{ 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1 \times 7 \times 6 \times 5 \times 4 \times3  \times 2 \times 1 }  = 5   \times 3 \times 8 \:  = 120 \: ans

Hence the correct answer is 120Ways

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