Question

There are three resistors joined in series in a system having resistance equal to 10 Ω, 20 Ω and 30 Ω respectively. If the potential difference of the circuit is 240 V, find the total resistance and current through the circuit.

Answer 1

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Answer 2

Given,

There are three resistors joined in series in a system having resistance equal to 10 Ω, 20 Ω and 30 Ω respectively.

To Find,

If the potential difference of the circuit is 240 V, find the total resistance and current through the circuit.

Solution,

We can solve the question as follows:

It is given that three resistors having resistance equal to 10 Ω, 20 Ω and 30 Ω are connected in series.

We know that when two or more resistors are connected in series, the total resistance is equal to the sum of their individual resistances.

Therefore,

$R_{Total} = R_{1} + R_{2} + R_{3}$

$R_{Total} = 10 + 20 + 30$

$R_{Total} = 60$ Ω

Now, we have to find the current through the circuit.

It is given that the potential difference, V of the circuit is equal to 240 V.

According to Ohm's Law, the current through a circuit is equal to the potential difference divided by the total resistance.

$I = \frac{V}{R}$

Here, $V = 240 V$

         $R = 60 ohms$

Substituting the values,

$I = \frac{240}{60}$

  $= 4 A$

Hence, the total resistance and current through the circuit are 60 ohms and 4 A respectively.