Question

THERE ARE THREE RESISTORS JOINED IN SERIES IN A SYSTEM HAVING RESISTENCE EQUAL TO 10 OHM,20 OHM AND 30 OHM RESPECTIVELY. IF THE POTENTIAL DIFFERENCE OF THE CIRCUIT IS 240 V, FIND THE TOTAL RESISTENCE AND CURRENT THROUGH THE CIRCUIT.

Answer 1

Answer:-

• R1=10ohm
• R2=20ohm
• R3=30ohm

We know

$\boxed{\sf R=R_1+R_2+R_3}$

$\\ \sf\longmapsto R=10+20+30$

$\\ \sf\longmapsto R=30+30$

$\\ \sf\longmapsto R=60\Omega$

• Potential difference=240V
• Current=I

According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \sf\longmapsto I=\dfrac{V}{R}$

$\\ \sf\longmapsto I=\dfrac{240}{60}$

$\\ \sf\longmapsto I=4A$