THERE ARE THREE RESISTORS OF 2 ohm, 3 ohm, AND 6 ohm.WHAT IS THE LEAST RESISTANCE THAT WE CAN MAKE OUT OF FROM THIS BY COMBINING THESE THREE?
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Answers
Answer:
Least equivalent resistance obtained on combing three resistors 2 Ω , 3 Ω and 6 Ω is 1 Ω
Explanation:
A number of resistors give the minimum Equivalent resistance when they are connected in Parallel combination.
We are given with three resistors of resistances 2 Ω , 3 Ω , 6 Ω
Using the Law of combination of resistors in parallel combination , that is stated as :
Reciprocal of the combined resistances of a number of resistances connected in parallel is equal to the sum of the reciprocals of all the individual resistances .
1/R = 1/R₁ + 1/R₂ + 1/R₃ + .....
●Calculating the equivalent resistance of circuit when 2 Ω , 3 Ω and 6 Ω resistors are connected in Parallel to get least resistance.
Let, their equivalent resistance be R
→ 1/R = 1/2 + 1/3 + 1/6
→ 1/R = ( 3 + 2 + 1 ) / 6
→ 1/R = 6 / 6
→ 1 / R = 1
→ R = 1 Ω
Therefore,
The least resistance we can make out from combining three resistors as 2Ω , 3Ω and 6Ω is 1 ohm .