Math, asked by Harshharry2245, 1 year ago

There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?

Answers

Answered by Anonymous
0
= 12 ways. Hence, the total number of words = 2 x 12 = 24. Problems on Permutations and Combinations : Question 7 : There are three rooms in a motel: one single, one double and one for four persons

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Answered by Anonymous
0
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There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?

=> 12 × 2 = 24



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