there are three section of class 10th in Kendriya Vidyalaya Delhi Cantt the total number of strain in class 10th 400 the marks obtained by the students in pre board exam are presented in the table as given below the mean of the marks obtained in 53
Marks obtained=0-20,20-40,40-60,60-80,80-100
Number of student 15,18,21,29,p
(1) how many students got marks between 80-100?
a)21 (b)38 (c) 17 (d)26 (2) what is the lower limit of modal class a)20 (b)40 (c)60 (d) 80 (3) what is the value of modal marks
(a)58 (b)62 (c) 65 (d) 68 (4) what is the value of {fixi? (a)2900 (b) 5300 (c) 1500 (d) 100
(5) what is the upper limit of the median class?
(a) 20 (b) 40 (c) 60 (d) 80
Answers
Given :
Marks obtained= 0-20,20-40,40-60,60-80,80-100
Number of student 15 , 18, 21, 29, p
mean of the marks obtained is 53
To Find : (1) how many students got marks between 80-100?
a)21 (b)38 (c) 17 (d)26 (2)
what is the lower limit of modal class a)20 (b)40 (c)60 (d) 80
what is the value of modal marks
(a)58 (b)62 (c) 65 (d) 68
what is the value of {fixi? (a)2900 (b) 5300 (c) 1500 (d) 100
what is the upper limit of the median class?
(a) 20 (b) 40 (c) 60 (d) 80
Solution:
Marks obtained class mark x f fixi
0-20, 10 15 150
20-40, 30 18 540
40-60, 50 21 1050
60-80, 70 29 2030
80-100 90 p 90p
Total 83+p 3770 + 90p
Mean = (3770 + 90p)/(83 + p) = 53
=> 3770 + 90p = 83 * 53 + 53p
=> 37p = 629
=> p = 17
17 students got marks between 80-100
Modal class 60-80 with f = 29
lower limit of modal class 60
Mode = 60 + 20 * (29 - 21)/(29 - 21 + 29 - 17)
= 60 + 20 * 8/20
= 68
value of modal marks = 68
∑fixi = 3770 + 90p = 3770 + 90(17) = 5300
83 + p = 83 + 17 = 100
100/2 = 50
15 + 18 + 21 = 54 > 50
Median class = 40-60
upper limit of the median class 60
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Answer:
arks obtained= 0-20,20-40,40-60,60-80,80-100
Number of student 15 , 18, 21, 29, p
mean of the marks obtained is 53
To Find : (1) how many students got marks between 80-100?
a)21 (b)38 (c) 17 (d)26 (2)
what is the lower limit of modal class a)20 (b)40 (c)60 (d) 80
what is the value of modal marks
(a)58 (b)62 (c) 65 (d) 68
what is the value of {fixi? (a)2900 (b) 5300 (c) 1500 (d) 100
what is the upper limit of the median class?
(a) 20 (b) 40 (c) 60 (d) 80
Solution:
Marks obtained class mark x f fixi
0-20, 10 15 150
20-40, 30 18 540
40-60, 50 21 1050
60-80, 70 29 2030
80-100 90 p 90p
Total 83+p 3770 + 90p
Mean = (3770 + 90p)/(83 + p) = 53
=> 3770 + 90p = 83 * 53 + 53p
=> 37p = 629
=> p = 17
17 students got marks between 80-100
Modal class 60-80 with f = 29
lower limit of modal class 60
Mode = 60 + 20 * (29 - 21)/(29 - 21 + 29 - 17)
= 60 + 20 * 8/20
= 68
value of modal marks = 68
∑fixi = 3770 + 90p = 3770 + 90(17) = 5300
83 + p = 83 + 17 = 100
100/2 = 50
15 + 18 + 21 = 54 > 50
Median class = 40-60
upper limit of the median class 60