Math, asked by ptvhoa2008, 4 months ago

There are three sticks: A, B, and C. The length of Stick A is 82% of the length of stick B. The length of stick B is 60% the length of stick C. If B is 270 cm long, how many centimeters shorter is A than C?

Answers

Answered by vedasree01
1

Answer:

228.6 cm.

Step-by-step explanation:

let the lengths of sticks A,B,C be a,b,c respectively.

given,

a=0.82b and b=0.6c

and b=270cm.

a=0.82*270

a=221.4 cm.

and 270= 0.6c

c = 450 cm.

required is 450 - 221.4 = 228.6

Answered by khashrul
1

Answer:

Stick A is 228 cm and 6 mm shorter than Stick C

Step-by-step explanation:

Stick B is 270 cm long

Stick A is 82% of the length of Stick B =\frac{82}{100}  of 270 cm =221.4 cm long

Stick B is 60% of the length of Stick C

∴ Stick C is 1/(60%) =\frac{100}{60} of Stick B =\frac{5}{3}  of 270 cm = 450 cm long

∴ Stick A is (450 - 221.4) cm = 228.6 cm = 228 cm and 6 mm shorter than Stick C

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